Which of the following orders is true regarding the basic nature of $- N H_{2}$ group?

o - T o l u i d i n e > A n i l i n e > o - N i t r o a n i l i n e

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o - T o l u i d i n e < A n i l i n e > o - N i t r o a n i l i n e

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o - T o l u i d i n e < A n i l i n e < o - N i t r o a n i l i n e

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o - T o l u i d i n e > A n i l i n e < o - N i t r o a n i l i n e

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Solution

The correct option is B $o - T o l u i d i n e < A n i l i n e > o - N i t r o a n i l i n e$
The correct order of basic strength of aromatic amines is $o - T o l u i d i n e < A n i l i n e > o - N i t r o a n i l i n e$ .

Aniline is more basic than ortho nitro aniline because the presence of electron withdrawing nitro group decreases the ease with which N can donate a lonepair of electrons.

o-Toluidine is less basic than aniline because whenever a substituent is present in the ortho position, it decreases its basicity.

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Which of the following orders is true regarding the basic nature of NH₂ group?

o -

m -

p -

- N H_{2}

p K_{b}

C_{2} H_{5} N H_{2}, C_{6} H_{5} N H C H_{3}, (C_{2} H_{5})_{2} N H

C_{6} H_{5} N H_{2}

C_{6} H_{5} N H_{2}, C_{6} H_{5} N (C H_{3})_{2}, (C_{2} H_{5})_{2} N H

C H_{3} N H_{2}

C H_{3} N H_{2}

C_{6} H_{5} N H_{2}

N H_{2}

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