Question

Which of the following orders regarding the boiling point of halogens is true?

• A. $HF>$ $HCI>$ $HBr$ $>HI$
• B. $HF<$ $HCI<$ $HBr$ $<HI$
• C. $HF>$ $HCI<$ $HBr$ $<HI$
• D. $HF>$ $HCI>$ $HBr$ $<HI$

Answer 1

The correct option is C $HF>$ $HCI<$ $HBr$ $<HI$

HF has the maximum ionic due to the largest electronegative difference between H and F and there is H-bonding.

HCl, HBr, and HI are polar covalent.

The boiling point of covalent$\alpha Molarmass$

$\therefore HI>HBr>HCl$

Since the boiling point of ionic > covalent

$\therefore HF>HCl<HBr<HI$