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Question

Which of the following orders with regards to the basic strength of substituted aniline is correct?

A
p - methylaniline > p - chloroaniline > p - aminoacetophenone
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B
p - methylaniline > p - aminoacetophenone > p - chloroaniline
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C
p - aminoacetophenone > p - methylaniline > p - chloroaniline
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D
p - aminoacetophenone > p - chloroaniline > p - methylaniline
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Solution

The correct option is A p - methylaniline > p - chloroaniline > p - aminoacetophenone
The methyl group is a strong electron releasing group. Hence, p - methylaniline is most basic.
Halogens and carbonyl groups are weakly deactivating or weak electron-withdrawing groups.
The order of the ability to withdraw electron density is carbonyl > halogen > alkyl.
The higher the ability of the substituent to withdraw electrons, lower is the basicity of amine.
Hence, the order of basicity is p - methylaniline > p - chloroaniline > p - aminoacetophenone.

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