Which of the following oxide dissolves in water to form an acidic solution?

N a_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C a O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A l_{2} O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Z n O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E $S O_{3}$
Sulphur trioxide is an oxide of sulphur that reacts with water to form sulphuric acid. The solution is an acidic solution.
$S O_{3} + H_{2} O \to H_{2} S O_{4}$

Suggest Corrections

Similar questions

C a O

M g O

C O_{2}

S O_{3}

N a_{2} O

Z n O

A l_{2} O_{3}

F e_{2} O_{3}

Classify ${Na}_{2} O$ , ${Al}_{2} O_{3}$ and ${SO}_{3}$ as acidic, basic or amphoteric oxide. [3 MARKS]

N a_{2} O, K_{2} O, S O_{2}, S O_{3}, C O_{2}, Z n O, A l_{2} O_{3}

Join BYJU'S Learning Program