Which of the following pair of gases cannot be separated by diffusion method?

S O_{2}

and

H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C O_{2}

and

N_{2} O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N H_{3}

and

N_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C O_{2}

and

H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $C O_{2}$ and $N_{2} O$
Previously we told that, $D \propto \frac{1}{\sqrt{M}}$
Now, $M_{C O_{2}}$ $= 2 \times 16 + 12 = 44$ g/mol
$M_{N_{2} O}$ $= 2 \times 14 + 16 = 44$ g/mol
$∴ D_{C O_{2}} = D_{N_{2} O}$ , as diffusion coefficient of $C O_{2}$ and $N_{2} O$ is equal, $C O_{2}$ and $N_{2} O$ cannot be separated by diffusion method.

Suggest Corrections

Similar questions

The volumes of gases $H_{2}, C H_{4}, C O_{2} a n d N H_{3}$ absorbed by 1 g of charcoal at 288 K are in the order:

C O_{2}, C H_{4}, C O, N H_{3}, water vapour, N_{2} O, O_{2}, S O_{2}, N_{2}, hydrofluorocarbons, O_{3}, C F C

O_{2}

H_{2}

C O_{2}

O_{2}, H_{2}

C O_{2}

H_{2}, O_{2}, N H_{3}

C O_{2}

Join BYJU'S Learning Program