Which of the following pairs are members of a homologous series?

C H_{3} O C H_{3}; C H_{3} C H_{2} O H

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C H_{3} C H O; C H_{3} C H_{2} C H O

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C H_{3} C H_{2} C O O H; C H_{3} C O O C H_{3}

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(C H_{3})_{2} C H O H; C H_{3} C H_{2} O H

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Solution

The correct option is B $C H_{3} C H O; C H_{3} C H_{2} C H O$
Acetaldehyde i.e $C H_{3} C H O$ and propionaldehyde i.e $C H_{3} C H_{2} C H O$ belong from the aldehyde family hence they are homologous series.
Hence, option B is the correct answer.

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Similar questions

C H_{3} C H_{2} C H_{3}, C H_{3} C H O, C H_{3} C H_{2} O H, C H_{3} O C H_{3}

Arrange the following compounds in increasing order of their boiling points.

CH₃CHO, CH₃CH₂OH, CH₃OCH₃, CH₃CH₂CH₃

C H_{3} C H_{2} O H

C H_{3} O C H_{3}

C H_{3} C H_{2} O H + H C l a n h . Z n C l_{2} - ----- \to

C H_{3} C H_{2} O H + H C l \to

(C H_{3})_{3} C O H + H C l \to

(C H_{3})_{2} C H O H + H C l a n h . Z n C l_{2} - ----- \to

C H_{3} C H_{2} O H

C H_{3} C H O

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