Which of the following pairs is correctly matched?
List I List II
Amethyst Kashmir
Lead Maharasthra
Conch Saurashtra
Turquoise Persia
Jade Central Asia

1, 2, 3 and 4

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3, 4 and 5

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1 and 2

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3 and 5

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Solution

The correct option is D 3, 4 and 5
Amethyst is a precious stone consisting of a violet or purple variety of quartz. It was found in Maharashtra during the harappan times.
Lead was from Kashmir.
Conch is a tropical marine mollusc with a robust spiral shell which may bear long projections and have a flared lip. Conch was found from Saurashtra during harappan era.
Turquoise is a semi-precious stone, typically opaque and of a greenish-blue or sky-blue colour, consisting of a hydrated phosphate of copper and aluminium. It was from Persia.
Jade is a hard, typically green stone used for ornaments and implements and consisting of the minerals jadeite or nephrite. It was found in Persia during harappan times.

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\frac{x + 4}{3} = \frac{y - 1}{5} = \frac{z + 3}{4} and \frac{x + 1}{1} = \frac{y - 4}{1} = \frac{z - 5}{2}

\frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{- 3} and \frac{x + 3}{- 1} = \frac{y - 5}{8} = \frac{z - 1}{4}

\frac{5 - x}{- 2} = \frac{y + 3}{1} = \frac{1 - z}{3} and \frac{x}{3} = \frac{1 - y}{- 2} = \frac{z + 5}{- 1}

\frac{x - 2}{3} = \frac{y + 3}{- 2}, z = 5 and \frac{x + 1}{1} = \frac{2 y - 3}{3} = \frac{z - 5}{2}

\frac{x - 5}{1} = \frac{2 y + 6}{- 2} = \frac{z - 3}{1} and \frac{x - 2}{3} = \frac{y + 1}{4} = \frac{z - 6}{5}

\frac{- x + 2}{- 2} = \frac{y - 1}{7} = \frac{z + 3}{- 3} and \frac{x + 2}{- 1} = \frac{2 y - 8}{4} = \frac{z - 5}{4}

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