Which of the following pairs of cations cannot be separated by using dilute $H C l$ ?

H g_{2}^{2 +}, P b^{2 +}

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H g^{2 +}, A g^{+}

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A g^{+}, C u^{2 +}

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H g_{2}^{2 +}, B i^{3 +}

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Solution

The correct option is B $H g_{2}^{2 +}, P b^{2 +}$
As $H g_{2}^{2 +}$ and $P b^{2 +}$ both belong to same group (1st group). So both give white ppt with dilute $H C l$ so can not be separated.
$P b^{2 +} + 2 H C l \to P b C l_{2}$ (white ppt.)
$H g_{2}^{2 +} + 2 H C l \to H g_{2} C l_{2}$ (white ppt.) $+ 2 H N O_{3}$

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