Question

Which of the following pairs of complexes are isomeric with each other but their aqueous solutions exhibit different molar conductivities?

• A. $\left[PtC{l}_2\right(N{H}_3{)}_4\left]B{r}_{2}and\right[PtB{r}_2\left(N{H}_3{)}_4\right](OH{)}_2$
• B. $\left[Pt\right(OH{)}_2\left(N{H}_3{)}_4\right]S{O}_{4}and\left[PtS{O}_4\right(N{H}_3{)}_4\left]\right(OH{)}_2$
• C. $K_3\left[Fe\right(CN{)}_2\left]and{K}_4\right[Fe\left(CN{)}_6\right]$
• D. $\left[Co\right(N{H}_3{)}_{5}Br\left]S{O}_{4}and\right[Co\left(N{H}_3{)}_{5}S{O}_4\right]CI$

Answer 1

The correct option is B

$\left[Pt\right(OH{)}_2\left(N{H}_3{)}_4\right]S{O}_{4}and\left[PtS{O}_4\right(N{H}_3{)}_4\left]\right(OH{)}_2$

$\left[Pt\right(OH{)}_2\left(N{H}_3{)}_4\right]S{O}_4\to \left[Pt\right(OH{)}_2(N{H}_3{)}_4{]}^{+2}+S{O}_4^{-2}$

$\left[PtS{O}_4\right(N{H}_3{)}_4\left]\right(OH{)}_2\to \left[PtS{O}_4\right(N{H}_3{)}_4{]}^{+}2+2O{H}^{-}$

The complexes are ionization isomers, as they differ in number of ions and they have different molar conductivities due to different number of ions.