Question

Which of the following pairs of compounds has same number of valence electrons and also isostructural ?

• A. $I{F}_3,Xe{F}_2$
• B. $BeC{l}_2,Xe{F}_2$
• C. $Te{I}_2,Xe{F}_2$
• D. $IB{r}_2^{-},Xe{F}_2$

Answer 1

The correct option is D $IB{r}_2^{-},Xe{F}_2$

Only $IB{r}_2^{-}$ and $Xe{F}_2$ are linear and hence isostructural and have the same number of valence electrons i.e. (22).
In both, the central atoms $I^{-}$ and $Xe$ have 2 bond pairs and 3 lone pair of electrons such that the molecule has linear geometry. Thus correct option is (d).
$I{F}_3$ has T-shape and has 28 electron while $Xe{F}_2$ has linear shape and has linear shape.
$BeC{l}_2$ has linear shape and has 16 electron while $Xe{F}_2$ has linear shape and has 22 electron.
$Te{I}_2$ has bent shape and has 20 electron while $Xe{F}_2$ has linear shape and has 22 electron.