Which of the following pairs of elements show similar set of oxidation state?

O^{16}, O^{18}

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N a, K

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C, B e

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Z n, R b

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Solution

The correct option is D $O^{16}, O^{18}$
Oxidation state is decided by number of electrons an element loose or gain.In isotopes number of electrons are same but mass number is different. In $O^{16}$ and $O^{18}$ mass number is differnet 16 and 18 respectively and both have same oxidation state 2.

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Similar questions

Which of the sets of elements follows Newland’s octave rule:-

A)Be,Mg,Ca

B)Na,K,Rb

C)F,Cl,Br

D)B,Al,Ga

and how?

O, C l, F, N, P, S n, T l, N a, T i

{C H}_{3} -^{16} C - O^{18} - C_{2} H_{5} + H_{2} O^{16} H e a t - -- \to H^{+}

Out of $O^{16}$ and $O^{18}$ isotopes, which has more number of neutrons?

K_{2} M n O_{4}

M n O_{2}

{N a}_{2} {C r}_{2} O_{7}

{N a}_{2} C r O_{4}

{M n}^{2 +}

{F e}^{2 +}

+ 3

Z n

3 d

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