Which of the following pairs of species (atoms/ions) will have identical ground state electronic configuration?

L i^{+} a n d H e^{-}

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C l^{-} a n d A r

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N a a n d K

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F^{+} a n d N e

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Solution

The correct option is B $C l^{-} a n d A r$
Species with the same number of electrons will have identical electronic configuration.
$L i^{+}$ = $1 s^{2}$ and $H e^{-}$ = $1 s^{2} 2 s^{1}$
$C l^{-}$ = $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$
$A r = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$
$N a = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$
$K = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}$
$F^{+}$ = $1 s^{2} 2 s^{2} 2 p^{4}$
$N e = 1 s^{2} 2 s^{2} 2 p^{6}$

Hence, $C l^{-} a n d A r$ have the same electronic configuration.

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1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}

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