Question

Which of the following particles is emitted in the nuclear reaction :
${}_{13}A{l}^{27}{+}_{2}h{e}^4{\to }_{14}{P}^{30}+......$

• A. ${}_0{n}^1$
• B. ${}_{-1}{e}^0$
• C. ${}_1{H}^1$
• D. ${}_1{H}^2$

Answer 1

The correct option is C ${}_1{H}^1$

${}_{13}A{l}^{27}{+}_{2}h{e}^4{\to }_{14}{P}^{30}{+}_Z{X}^A$
Equating mass number of both sides
$27+4=30+A$
$\therefore$ $A=31-30=1$
equating atomic number of both sides
$13+2=14+Z$
$\therefore$ $Z=1$
$\therefore$ Particle is ${}_1{H}^1$.