Which of the following particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field?
(a) Electron
(b) Proton
(c) He⁺
(d) Li⁺

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Solution

(d) Li⁺

Time period of the revolution of the particle, $T = \frac{2 π m}{q B}$
As frequency is the reciprocal of time period, so $f = \frac{q B}{2 π m}$
The charge on all the four particles is same. But the mass is maximum for Li⁺. So, it will have the smallest frequency of revolution.

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Which of the following particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field? (a) Electron (b) Proton (c) He+ (d) Li+

(d) Li+ Time period of the revolution of the particle, T = 2πmqB As frequency is the reciprocal of time period, so f = qB2πm The charge on all the four particles is same. But the mass is maximum for Li+. So, it will have the smallest frequency of revolution.

Which of the following particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field?
(a) Electron
(b) Proton
(c) He⁺
(d) Li⁺

(d) Li⁺

Time period of the revolution of the particle, $T = \frac{2 π m}{q B}$
As frequency is the reciprocal of time period, so $f = \frac{q B}{2 π m}$
The charge on all the four particles is same. But the mass is maximum for Li⁺. So, it will have the smallest frequency of revolution.