Question

Which of the following plane is equally inclined to the planes 4x + 3y – 5z = 0 and 5x – 12y + 13z = 0 is

• A. 11x – 3y = 0
• B. 3x + 11y = 0
• C. 3x + 11y – 65z = 0
• D. 11x + 3y = 0

Answer 1

The correct option is A

11x – 3y = 0

The required plane is the plane bisecting the angle between them. $\therefore$ $\frac{4x+3y-5z}{5\sqrt{2}}=\pm \left(\frac{5x-12y-13z}{13\sqrt{2}}\right)$