Question

Which of the following plots does not represent Boyle’s law?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

From Boyle’s Law, $PV=Constant$
$P=\frac{K}{V}$
Taking log on both side, we get:
$logP=logK-logV$
$logP=logK+log{V}^{-1}$---(i)
On comparing equation (i) with the equation of a straight line i.e y = c + mx,
We get the slope for the graph between log P and $\text{log}{V}^{-1}$ is +1.
Whereas, for option $\left(c\right)$, $\text{slope}=tan{135}^{\circ }=-1$
So, option $\left(c\right)$ is does not represent Boyle's law.
The different graphical representations of Boyle’s Law are: