Which of the following polynomials has -3 as a zero?

(x - 3)

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x² - 3x

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x² - 9

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x² + 3

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Solution

The correct option is C
x² - 9

Let p(x) = x² - 9

Therefore, p(-3) = 9 - 9 = 0.

So -3 is the zero of p(x).

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