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Periodic Properties

Which of the ...

Question

Which of the following possesses the highest bond energy?

F_{2}

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C l_{2}

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B r_{2}

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I_{2}

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Solution

The correct option is B $C l_{2}$
$F_{2}$ is a smaller molecule than $C l_{2}$ . This means that the bonded electrons in $F_{2}$ are closer to the outer shell unbonded electrons. Due to the electron repulsion theory, the bonded electrons repel the outer shell unbonded electrons far more in $F_{2}$ than they would in $C l_{2}$ .

since $C l_{2}$ has more shells so more shielding of the outer electrons. The fact that the bonded electrons in $F_{2}$ repel the unbonded electrons so much makes the molecule weak, so it is easier to break.

Hence option B is correect.

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Similar questions

F_{2}, C l_{2}, B r_{2}, I_{2}

C l_{2} > B r_{2} > F_{2} > I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

{C l}_{2}, {B r}_{2}

I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

C l > F > B r > I

F > C l > B r > I

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