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Question

Which of the following products is formed in good yield by the reduction of methyl 4-oxo-hexanoate (M) with NaBH4?

508509_19b61880e0044d518c560e776ec0e19f.png

A
Methyl 4-hydroxyhexanoate
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B
1,4-Hexanediol
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C
6-Hydroxy-3-hexanone
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D
4-Hydroxyhexanal
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Solution

The correct option is A Methyl 4-hydroxyhexanoate
Sodium borohydride reduces ketone to a secondary alcohol. Sodium borohydride does not reduce ester.

Hence the correct option is A.

828912_508509_ans_f2865b6c815a454e9f0f6a9e6a12c31d.png

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