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Quantum Number

Which of the ...

Question

Which of the following properties of an element is allowable:

n = 2, l = 1, m =0, s = + 1/2

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n = 2, l = 2, m = -1, s = -1/2

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n = 2, l = -2, m = 1, s = + 1/2

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n = 2, l = 1, m = 0, s = 0

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Solution

The correct option is A n = 2, l = 1, m =0, s = + 1/2
As we know, $n \neq l$ and s can not be zero so only this set is possible:
n = 2, l = 1, m =0, s = + 1/2.

Suggest Corrections

Similar questions

n = 4, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}

n = 3, l = 1, m_{l} = 1, m_{s} = - \frac{1}{2}

n = 3, l = 2, m_{l} = 0, m_{s} = + \frac{1}{2}

n = 3, l = 0, m_{l} = 0, m_{s} = - \frac{1}{2}

n = 0

l = 0

m_{1} = 0

m_{s} = + 1 / 2

n = 1

l = 0

m_{1} = 0

m_{s} = - 1 / 2

n = 1

l = 1

m_{1} = 0

m_{s} = + 1 / 2

n = 2

l = 1

m_{1} = 0

m_{s} = - 1 / 2

n = 2

l = 3

m_{1} = - 3

m_{s} = + 1 / 2

n = 3

l = 1

m_{1} = 0

m_{s} = + 1 / 2

Which set of quantum numbers is possible for the last electron of Mg⁺ ion?

n = 4, l = 0, m = 0, s = + \frac{1}{2}

n = 3, l = 1, m = 1, s = - \frac{1}{2}

n = 3, l = 2, m = 0, s = + \frac{1}{2}

n = 3, l = 0, m = 0, s = - \frac{1}{2}

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