MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Magnetic Field Due to Finite Wire

Which of the ...

Question

Which of the following quantities are always zero in SHM?

A

\to F \times \to a

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

\to v \times \to r

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

\to a \times \to r

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

\to F \times \to r

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A $\to F \times \to a$
B $\to v \times \to r$
C $\to a \times \to r$
D $\to F \times \to r$
In SHM $\to F$ , $\to r$ , $\to v$ and $\to a$ are always along the same straight line either in the same direction or in opposite directions, so the angle between any of the pairs is either $0^{\circ}$ or $180^{\circ}$ and $sin 0^{\circ} = sin 180^{\circ} = 0$ . So cross product of any of the pair will also be equal to zero. Hence all options are correct.

Suggest Corrections

thumbs-up

0

Similar questions

\to a, \to b, \to c

are three non-coplanar non-zero vectors and

\to r

is any vector, then

(\to a \times \to b) \times (\to r \times \to c) + (\to b \times \to c) \times (\to r \times \to a) + (\to c \times \to a) \times (\to r \times \to b) =

Q. Assertion :If

\to r \times \to a = \to b, \to r . \to a = 1,

\to r = \to a + \to a \times \to b .

Reason: The solution of the

\to r \times \to a = \to b

\to r = \to a \times \to b

.

\to a, \to b, \to c

are three noncoplanar nonzero vectors and

\to r

is any vector in space then

(\to a \times \to b) \times (\to r \times \to c) + (\to b \times \to c \times (\to r \times \to a) + (\to c \times \to a) \times (\to r \times \to b)

\to r \times \to a = \to b \times \to a; \to r \times \to b = \to a \times \to b; \to a \neq 0, \to b \neq 0, \to a \neq λ \to b; \to a

is not perpendicular to

\to b

\to r =

\to a = \to i + \to j

\to b = 2 \to j - \to k

\to r \times \to a = \to b \times \to a

\to r \times \to b = \to a \times \to b

\frac{\to r}{| \to r |}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Magnetic Field Due to a Current Carrying Wire

PHYSICS

Watch in App

explore_more_icon

Explore more

Magnetic Field Due to Finite Wire

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon