Question

Which of the following ratio will give stability to daughter element, when radioactive parent element has less number of protons compared to number of neutrons?

• A. $\frac{N+1}{Z+1}$
• B. $\frac{N-1}{Z+1}$
• C. $\frac{N-1}{Z-1}$
• D. $\frac{N+1}{Z-1}$

Answer 1

The correct option is B $\frac{N-1}{Z+1}$

The nuclei which are richer in neutron lying above the belt of stability, they disintegrate in such a manner that one of their neutron is converted into a proton.
$\left[{}_0^{1}n\underset{}{\overset{}{\to }}{}_1^{1}Hor{}_1^{1}P{+}_{-1}^{0}e(\beta -particle)\right]$
i.e., After emitting a $\beta$-particle the newly-formed nucleide has its $n/p$ value lower than its parent nucleide and hence approaches closer to the zone of stability and become stable.
Hence, stability ratio of daughter element is
$\frac{N-1}{Z+1}$.