Which of the following rational numbers is in the standard form?

\frac{8}{- 36}

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\frac{- 7}{53}

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\frac{3}{- 4}

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None of these

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Solution

The correct options are
A $\frac{- 7}{53}$
C $\frac{3}{- 4}$
We know that a rational number $\frac{a}{b}$ is said to be in the standard form if the denominator $b$ is positive, and the integers $a$ and $b$ have no common divisor other than $1$ .

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Similar questions

Express each of the following rational numbers in standard form :

(i) $\frac{- 12}{30}$ (ii) $\frac{- 14}{49}$ (iii) $\frac{24}{- 64}$ (iv) $\frac{- 36}{- 63}$

\frac{8}{12}

\frac{4}{6}

\frac{- 12}{30}

\frac{- 14}{49}

\frac{24}{- 64}

\frac{- 36}{- 63}

\frac{7}{8}, \frac{36}{- 12}, \frac{5}{- 4}, \frac{- 2}{3}

Which of the following rational numbers lie betwen $\frac{3}{7}$ and $\frac{4}{8}$ ?

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