Which of the following reaction has zero activation energy?

{C H}_{4} + ∙ C l \to ∙ C H_{3} H C l

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{C l}_{2} \to 2 C l

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∙ C H_{3} + ∙ C H_{3} + {C H}_{3} + {C H}_{3}

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∙ C H_{3} + C l - C l \to {C H}_{3} + C l + ∙ C l

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Solution

The correct option is A ${C H}_{4} + ∙ C l \to ∙ C H_{3} H C l$
Among the given reactions
${˙ C H}_{3} + {˙ C H}_{3} \to {C H}_{3} - {C H}_{3}$ has zero activation energy.
All the other reactions are following a free radial which needs energy in the form $U . V$ light which is high activation energy.
Where as in the above reaction the free radicals are bonded together by lowering their energy thus by increasing the stability.
So, the reaction
${˙ C H}_{3} + {˙ C H}_{3} \to {C H}_{3} - {C H}_{3}$ has zero activation energy.

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Similar questions

(1) C l_{2} \to ∙ 2 C l (2) ∙ C H_{3} + ∙ C H_{3} \to C H_{3} - C H_{3} (3) ∙ C l + C H_{4} \to C H_{3} C l + ∙ C l (4) ∙ C H_{3} + ∙ C l \to C H_{3} - C l (5) ∙ C H_{3} + C l_{2} \to C H_{3} - C l + ∙ C l

C l_{2} h v - \to C l^{∙} + C l^{∙}

C l^{∙} + C H_{4} \to^{∙} C H_{3} + H C l

C l^{∙} + C l^{∙} \to C l_{2}

^{∙} C H_{3} +^{∙} C l \to C H_{3} C l

S_{N} 2

C H_{3} - C l

C H_{3} - C | | O - C H_{2} - C l

C H_{3} - C H | C H_{3} - C H_{3} - C l

C H_{3} - C H_{2} - C l

\begin{matrix} C H_{3} - & C H & - C H_{2} - C l | C H_{3} \end{matrix}

\begin{matrix} C H_{3} - C H_{2} - & C H & - C l | C H_{3} \end{matrix}

S_{N} 1

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