Which of the following reaction involves diazonium salt as an intermediate?

C_{2} H_{5} N H_{2} + H N O_{2} N a N O_{2} - --- \to H C l [C_{2} H_{5} - N_{2}^{+} C l^{-}] H_{2} O - - \to C_{2} H_{5} O H + N_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{2} H_{5} N H_{2} + C H_{3} C H O H^{+} - - \to C H_{3} C H = N C H_{2} C H_{3} + H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} H_{5} N H_{2} + C H C l_{3} + 3 K O H w a r m - -- \to C H_{3} C H_{2} N C + 3 K C l + 3 H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{2} H_{5} N H_{2} + C_{6} H_{5} C O C l a q N a O H - ----- \to C_{2} H_{5} N H C O C_{6} H_{5} + H C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C_{2} H_{5} N H_{2} + H N O_{2} N a N O_{2} - --- \to H C l [C_{2} H_{5} - N_{2}^{+} C l^{-}] H_{2} O - - \to C_{2} H_{5} O H + N_{2}$
The following reaction involves diazonium salt as an intermediate.
$C_{2} H_{5} N H_{2} + H N O_{2} N a N O_{2} - --- \to H C l [C_{2} H_{5} - N_{2}^{+} C l^{-}] H_{2} O - - \to C_{2} H_{5} O H + N_{2}$
The diazonium salt is $[C_{2} H_{5} - N_{2}^{+} C l^{-}]$

Suggest Corrections

Similar questions

C_{2} H_{5} N H_{2} + H C l ⟶

(C H_{3})_{3} N, C_{2} H_{5} O H

C_{2} H_{5} N H_{2}

(i) $C_{2} H_{5} O H$

(ii) $(C H_{3})_{2} N H$

(iii) $C_{2} H_{5} N H_{2}$

Arrange the following in increasing order of their basic strength:

(i) C₂H₅NH₂, C₆H₅NH₂, NH₃, C₆H₅CH₂NH₂ and (C₂H₅)₂NH

(ii) C₂H₅NH₂, (C₂H₅)₂NH, (C₂H₅)₃N, C₆H₅NH₂

(iii) CH₃NH₂, (CH₃)₂NH, (CH₃)₃N, C₆H₅NH₂, C₆H₅CH₂NH₂.

Join BYJU'S Learning Program