Which of the following reaction is/are correct?

$N H_{4} C l + N a N O_{2} ⟶ N H_{4} N O_{2} + N a C l$

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$N H_{4} C l_{2} + N a N O_{2} ⟶ N H_{4} N O_{2} + N a C l_{2}$

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$C l_{2} + H_{2} O ⟶ H C l + H C L O$

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$C l_{2} + H_{2} O ⟶ H C l + H_{2} + O_{2}$

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Solution

The correct options are
A
$N H_{4} C l + N a N O_{2} ⟶ N H_{4} N O_{2} + N a C l$

C
$C l_{2} + H_{2} O ⟶ H C l + H C L O$

Since, $N H_{4}$ has a valency of +1 so option B is incorrect. Option A is properly balanced. Hence, it is correct.

$N H_{4} C l + N a N O_{2} ⟶ N H_{4} N O_{2} + N a C l$

When chlorine reacts with $H_{2} O$ it forms HCl and HClO. The HClO later breaks down to give HCl and [O]. Hence, option C is correct.

$C l_{2} + H_{2} O ⟶ H C l + H C l O$

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