Which of the following reaction is disproportionation reaction?

{C l}_{2} + {O H}^{-} \to

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H_{3} {P O}_{3} Δ - \to

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{M n O}_{4}^{- 2} + {O H}^{-} \to

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X e F_{4} + H_{2} O \to

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Solution

The correct option is B $H_{3} {P O}_{3} Δ - \to$
$4 H_{3} P O_{3} Δ - \to 3 H_{3} P O_{4} + P H_{3}$

In the reaction above, $H_{3} P O_{3}$ undergoes both oxidation and reduction to form phosphoric acid $H_{3} P O_{4}$ and phosphine $P H_{3}$ respectively which is by definition a disproportionation reaction.

Therefore, the option is B.

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Similar questions

C l_{2} + O H^{-} \to C l^{-} + C l O_{4}^{-} + H_{2} O

C l_{2} + K O H \to K C l O_{3} + K C l + H_{2} O

C l_{2} + O H^{-} \to C l^{-} + C l O_{3}^{-} + H_{2} O

H_{2} O + H_{2} O ⇌ H_{3} O^{+} + {O H}^{-}

C l_{2} + O H^{-} \to C l^{-} + C l O_{4}^{-} + H_{2} O

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