Question

Which of the following reaction is possible

Heating Copper oxide with Zinc or Magnesium.

Answer 1

Part:1

• When we heat Copper Oxide with Zinc it forms Zinc Oxide and Copper.
• As the reactivity of Zinc is more than Copper it can displace the Copper and carry the reaction forward.

$$\begin{gathered} \mathbf{CuO}\mathbf{}\mathbf{\left(}\mathbf{s}\mathbf{\right)}\mathbf{}\mathbf{+}\mathbf{}\mathbf{Zn}\mathbf{}\mathbf{\left(}\mathbf{s}\mathbf{\right)}\mathbf{}\stackrel{\mathbf{∆}}{\mathbf{\to }}\mathbf{}\mathbf{ZnO}\mathbf{}\mathbf{\left(}\mathbf{s}\mathbf{\right)}\mathbf{}\mathbf{+}\mathbf{}\mathbf{Cu}\mathbf{}\mathbf{\left(}\mathbf{s}\mathbf{\right)} \\ \mathbf{Copper}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{Zinc}\mathbf{} \\ \mathbf{Oxide}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{Oxide} \end{gathered}$$

• Hence, the reaction is possible

Part:2

• When we heat Copper Oxide with Magnesium it forms Magnesium Oxide and Copper.
• As the reactivity of Magnesium is more than Copper it can displace the Copper and carry the reaction forward.

$$\begin{gathered} \mathbf{CuO}\mathbf{}\mathbf{\left(}\mathbf{s}\mathbf{\right)}\mathbf{}\mathbf{+}\mathbf{}\mathbf{Mg}\mathbf{}\mathbf{\left(}\mathbf{s}\mathbf{\right)}\mathbf{}\stackrel{\mathbf{∆}}{\mathbf{\to }}\mathbf{}\mathbf{MgO}\mathbf{}\mathbf{\left(}\mathbf{s}\mathbf{\right)}\mathbf{}\mathbf{+}\mathbf{}\mathbf{Cu}\mathbf{}\mathbf{\left(}\mathbf{s}\mathbf{\right)} \\ \mathbf{Copper}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{Magnesium}\mathbf{} \\ \mathbf{Oxide}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{Oxide} \end{gathered}$$

• Hence, the reaction is possible