Which of the following reaction proceeds through a free radical mechanism?

(C H_{3})_{2} C H C H = C H_{2} + B r H ⟶ (C H_{3})_{2} C B r C H_{2} C H_{3}

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(C H_{3})_{2} C H C H = C H_{2} + B r_{2} ⟶ (C H_{3})_{2} C H C H B r C H_{2} B r

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(C H_{3})_{2} C H C H = C H_{2} + H B r R O O R - --- \to (C H_{3})_{2} C H C H_{2} C H_{2} B r

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(C H_{3})_{2} C H C H = C H_{2} + C l_{2} + H_{2} O ⟶ (C H_{3})_{2} C | H O H C H C H_{2} C l

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Solution

The correct option is D $(C H_{3})_{2} C H C H = C H_{2} + H B r R O O R - --- \to (C H_{3})_{2} C H C H_{2} C H_{2} B r$
$(C H_{3})_{2} C H C H = C H_{2} + H B r R O O R - --- \to (C H_{3})_{2} C H C H_{2} C H_{2} B r$

Addition of $H B r$ in presence of $R O O R$ proceeds through free radical mechanism. Net reaction is addition of a molecule of $H B r$ to $C = C$ double bond. Bromine is added to less substituted carbon atom.

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Similar questions

Q. When 2-chloro-2-methylbutane is heated with alcoholic

K O H

, the possible product(s) is/are:

i) (C H_{3})_{2} C = C H C H_{3}

i i) H_{2} C = C (C H_{3}) C H_{2} C H_{3}

i i) (C H_{3})_{2} C H C H = C H_{2}

The following reaction proceeds through which mechanism:

C H_{2} = C H_{2} + H B r \to C H_{3} - C H_{2} - B r

Which are free radical reactions

$I . C H_{3} - C H = C H_{2} + H B r P e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} B r I I . C H_{3} - C H = C H_{2} + H B r \to C H_{3} - C H B r - C H_{3} I I I . C H_{3} - C H = C H_{2} + C l_{2} \to C l C H_{2} - C H = C H_{2} I V . C H_{3} - C H_{3} + C l_{2} \to C l C H_{2} - C H_{3}$

Q. Explain the mechanism of the following reaction.

2 C H_{3} - C H_{2} - O H H^{+} - -- \to 413 K C H_{3} - C H_{2} - O - C H_{2} - C H_{3} + H_{2} O

Q. The reaction of propene with

H O C l (C l_{2} + H_{2} O)

proceeds through the intermediate:

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