Which of the following reaction products are correct?
Which of the following reaction products are correct?
The correct options are
B CH3−Cl+Ag−NO2⟶CH3−NO2+AgCl
D CH3−Cl+NaNO2⟶CH3−O−N=O+NaCl
We
check for all options whether it is correct or not:
(A) The bond between AgCN is not just same ,it will not easily broke as the bond between C and N in AgCN is triple bond . AgCN is mainly covalent
in nature and nitrogen is free to donate
electron pair forming isocyanide
as
the main product.
CH3−Cl + AgCN → CH3−NC + AgCl
Hence,
Option A is Incorrect.
(B) The
bond between Na and CN is IONIC,
Na gains +ve charge whereas CN gains -ve charge due to high electronegativity. Hence, the ionic bond between NaCN can be broken and easily separate due to difference in electronegativity and the bond which will form in product C-C is also strong
CH3−Cl + NaCN → CH3−CN + NaCl
Hence, Option B is Incorrect.
(C) On treating ethanolic
solution of nitroalkane with silver nitrite (Ag−O−N=O) nitroalkane is formed because since the bond
between Ag−O is covalent, the lone pair on
nitrogen acts as an attacking site for nucleophilic
substitution.
CH3−Cl + Ag−NO2 → CH3−NO2 + AgCl
Since, Option C is correct.
(D)
If haloalkane is treated with potassium nitrite, alkyl nitrite is
formed as major product because since
the bond between
Na-O is ionic in nature, the negative charge
on oxygen serves as an attacking site.
CH3−Cl + Na−NO2 → CH3−NO2 + NaCl
Hence,
Option D is correct.
Thus, Option C and D are correct.
B CH3−Cl+Ag−NO2⟶CH3−NO2+AgCl
D CH3−Cl+NaNO2⟶CH3−O−N=O+NaCl
We check for all options whether it is correct or not:
(A) The bond between AgCN is not just same ,it will not easily broke as the bond between C and N in AgCN is triple bond . AgCN is mainly covalent in nature and nitrogen is free to donate electron pair forming isocyanide
as the main product.
CH3−Cl + AgCN → CH3−NC + AgCl
Hence, Option A is Incorrect.
(B) The bond between Na and CN is IONIC,
Na gains +ve charge whereas CN gains -ve charge due to high electronegativity. Hence, the ionic bond between NaCN can be broken and easily separate due to difference in electronegativity and the bond which will form in product C-C is also strong
CH3−Cl + NaCN → CH3−CN + NaCl
Hence, Option B is Incorrect.
(C) On treating ethanolic solution of nitroalkane with silver nitrite (Ag−O−N=O) nitroalkane is formed because since the bond between Ag−O is covalent, the lone pair on nitrogen acts as an attacking site for nucleophilic substitution.
CH3−Cl + Ag−NO2 → CH3−NO2 + AgCl
Since, Option C is correct.
(D) If haloalkane is treated with potassium nitrite, alkyl nitrite is formed as major product because since
the bond between Na-O is ionic in nature, the negative charge
on oxygen serves as an attacking site.
CH3−Cl + Na−NO2 → CH3−NO2 + NaCl
Hence, Option D is correct.
Thus, Option C and D are correct.
