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Question

Which of the following reaction products are correct?

A
CH3Cl+AgCNCH3CN+AgCl
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B
CH3Cl+Na+CNCH3NC+NaCl
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C
CH3Cl+AgNO2CH3NO2+AgCl
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D
CH3Cl+NaNO2CH3ON=O+NaCl
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Solution

The correct options are
B CH3Cl+AgNO2CH3NO2+AgCl
D CH3Cl+NaNO2CH3ON=O+NaCl

We check for all options whether it is correct or not:

(A) The bond between AgCN is not just same ,it will not easily broke as the bond between C and N in AgCN is triple bond . AgCN is mainly covalent in nature and nitrogen is free to donate electron pair forming isocyanide

as the main product.

CH3Cl + AgCN CH3NC + AgCl

Hence, Option A is Incorrect.

(B) The bond between Na and CN is IONIC,

Na gains +ve charge whereas CN gains -ve charge due to high electronegativity. Hence, the ionic bond between NaCN can be broken and easily separate due to difference in electronegativity and the bond which will form in product C-C is also strong

CH3Cl + NaCN CH3CN + NaCl

Hence, Option B is Incorrect.

(C) On treating ethanolic solution of nitroalkane with silver nitrite (Ag−O−N=O) nitroalkane is formed because since the bond between Ag−O is covalent, the lone pair on nitrogen acts as an attacking site for nucleophilic substitution.

CH3Cl + AgNO2 CH3NO2 + AgCl

Since, Option C is correct.

(D) If haloalkane is treated with potassium nitrite, alkyl nitrite is formed as major product because since

the bond between Na-O is ionic in nature, the negative charge

on oxygen serves as an attacking site.

CH3Cl + NaNO2 CH3NO2 + NaCl

Hence, Option D is correct.

Thus, Option C and D are correct.


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