Which of the following reaction shows the reduction reaction of H2O2?
PbS + 4H2O2 → PbSO4 +4H2O
2I^- + 2H^+ + H2O2 → I2 + 2H2O
H2O2 + O3 → H2O + 2O2
K2Cr2O7 +H2SO4 +4H2O2→K2SO4 + 2CrO5 + 5H2O
H2O2 liberates electrons and O3 accepts electrons
Given :
Oxidation :
H2O2→O2+2H⊕+2e−
E⊖=−0.69V;
2F⊖→F2+2e−
E⊖=−2.87V;
Reduction :
H2O2+2H⊕+2e−→2H2O
E⊖=−1.77V;
2I⊖→I2+2e− E⊖=−0.54V;
Which of the following statements is/are correct ?