Which of the following reaction will give acetylene as a major product?

2 [C H_{3}] A g - \to △

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{3} C - C H_{2} - B r a l c . - - \to K O H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{2} | B r - C H_{2} | B r Z n - \to △

No worries! We‘ve got your back. Try BYJU‘S free classes today!

All of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2 [C H_{3}] A g - \to △$
Only $2 [C H_{3}] A g - \to Δ H C \equiv C H$ give acetylene
B) $H_{3} C - C H_{2} - B r a k - -- \to K O H C H_{2} = C H_{2}$
C) $C H_{2} | B r - C H_{2} | B r \to H_{2} C = C H_{2}$

Suggest Corrections

Similar questions

{CH}_{3} - {CH}_{2} - Br + {CH}_{3} - {CH}_{2} - Br Na / dry ether - ------- \to The product / s formed are

S_{N} 1

C H_{2} = C H_{2} + H B r \to C H_{3} - C H_{2} - B r

S_{N} 1

C H_{3} - C H_{2} - C H_{2} - B r

C H_{3} - C H - C H_{3}

B r

C H_{3} - C H_{2} - C H_{2} - C H_{2} - B r + C H_{3} O^{-} C H_{3} O H - ---- \to 60^{o} C P r o d u c t (I)

C H_{3} - C H_{2} - C H_{2} - C H_{2} - B r + (C H_{3})_{3} C O^{-} (C H_{3})_{3} C - O H - -------- \to 60^{o} C P r o d u c t (I I)

Join BYJU'S Learning Program