Which of the following reaction will give diborane as the product?

2 N a B H_{4} + I_{2} \to

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L i A l H_{4} + B F_{3} \to

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Both (A) and (B)

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None of these

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Solution

The correct option is C Both (A) and (B)
In both the reactions, $B_{2} H_{6}$ will be formed.
In (a), Boron trifluoride reacts with $L i A l H_{4}$ in diethyl ether to form diborane.
$2 N a B H_{4} + I_{2} \to B_{2} H_{6} + 2 N a I + H_{2} 0$

In (b),
$3 L i A l H_{4} + 4 B F_{3} e t h e r - -- \to 2 B_{2} H_{6} (↑) + 3 L i F + 3 A l F_{3}$
The above reation is the laboratory method for preparation of diborane.
In both the reaction diborane gas is evolved. Hence, the correct answer is option (c).

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Similar questions

B_{2} H_{6}

N a B H_{4} + I_{2} \to X + Y + Z

B F_{3} + N a H 450 K - -- \to X + P

B F_{3} + L i A l H_{4} \to X + Q + R

X, Y, Z, P

Q

Diborane reacts with ammonia under different condition to give a variety of products. Which of the following are formed in these conditions.

L i A l H_{4}

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