Which of the following reaction will not occur during the substitution reaction of methane with chlorine to form carbon tetrachloride?

C H C l_{3} (g) + C l_{2} (g) \to C C l_{4} (g) + H C l (g)

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C H_{2} C l_{2} (g) + C l_{2} (g) \to C H C l_{3} (g) + H C l (g)

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C H_{4} (g) + C l_{2} (g) \to C H_{2} C l_{2} (g) + H C l (g)

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C H_{3} C l (g) + C l_{2} (g) \to C H_{2} C l_{2} (g) + H C l (g)

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Solution

The correct option is C $C H_{4} (g) + C l_{2} (g) \to C H_{2} C l_{2} (g) + H C l (g)$
During the substitution reaction of methane with chlorine, the chlorine atoms replace one hydrogen in each step. This continues till all hydrogen atoms are replaced by chlorine atoms and carbon tetrachloride is formed. Following reactions take place during the substitution reaction of methane with chlorine to form carbon tetrachloride:
(i) $C H_{4} (g) + C l_{2} (g) \to C H_{3} C l (g) + H C l (g)$

(ii) $C H_{3} C l (g) + C l_{2} (g) \to C H_{2} C l_{2} (g) + H C l (g)$

(iii) $C H_{2} C l_{2} (g) + C l_{2} (g) \to C H C l_{3} (g) + H C l (g)$

(iv) $C H C l_{3} (g) + C l_{2} (g) \to C C l_{4} (g) + H C l (g)$

Since in each step only one hydrogen atom gets replaced by chlorine atom. Therefore, the reaction which will not occur during the substitution reaction of methane with chlorine to form carbon tetrachloride is given as:

$C H_{4} (g) + C l_{2} (g) \to C H_{2} C l_{2} (g) + H C l (g)$

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