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Preparation of Hydrogen

Which of the ...

Question

Which of the following reaction will not produce hydrogen gas?

Reaction between

F e

and dil.

H C l

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Reaction between

Z n

and conc.

H_{2} S O_{4}

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Reaction between

Z n

and

N a O H

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Electrolysis of

N a C l

in Nelson's cell

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Solution

The correct option is C Reaction between $Z n$ and conc. $H_{2} S O_{4}$
$a)$ $F e_{(s)} + 2 H C l_{(a q)} ⟶ F e C l_{2 (a q)} + H_{2 (g)}$
$b)$ $Z n + c o n c . 2 H_{2} S O_{4} ⟶ Z n S O_{4} + S O_{2} + 2 H_{2} O$
$c)$ $Z n + 2 N a O H ⟶ N a_{2} Z n O_{2} + H_{2}$
$d)$ In Nelson's cell, at cathode:
$2 H_{2} O + 2 e^{-} ⇌ H_{2} + 2 O H^{-}$
Hence, $B$ is the correct answer.

Suggest Corrections

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H_{2}

+

+

+

+

N a C l

H_{2} S O_{4}

H C l

K C l + H_{2} S O_{4} (c o n c .) \to

C u + H C l (d i l .) \to

C u O + H C l (d i l .) \to

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Z n \to Z n^{2 +} + 2 e^{-} (E_{(Z n^{2 +} / Z n)}^{0} = - 0.76 V)

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F e^{2 +} + Z n \to Z n^{2 +} + F e

H C l + N a O H \to N a C l + H_{2} O + x c a l

H_{2} S O_{4} + 2 N a O H \to N a_{2} S O_{4} + 2 H_{2} O + y c a l

x

y

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