Which of the following reaction will provide maximum voltage?
Given:
Zn2+(aq)+2e−→Zn(s); E0=−0.76 V
Cu2+(aq)+2e−→Cu(s); E0=0.34 V
Ag+(aq)+e−→Ag(s); E0=0.80 V
2H+(aq)+2e−→H2(g); E0=0 V
Ni2+(aq)+2e−→Ni(s); E0=−0.25 V
Standard reduction potentials (SRP) of the half cell electrodes are calculated and arranged in a series of increasing order which is known as electrochemical series.
The standard electrode potential of H+/H2 couple is zero.
Here, a negative E0 signifies that it has high tendency to get oxidised and the redox couple is a stronger reducing agent than the H+/H2 couple.
A positive E0 signifies that it has high tendency to get reduced and the redox couple is a stronger oxidising agent than the H+/H2 couple.
Electrochemical series helps in the selection of electrode assemblies to construct the galvanic cells of desired EMFs.
For a galvanic cell to provide high cell voltage, the half cell having higher reduction potential and lower reduction potential should be connected.
In the given half cell reactions,
Ag+(aq)+e−→Ag(s);(Highest value)
Zn2+(aq)+2e−→Zn(s);(Lowest value)
Hence, cell reaction providing maximum voltage will be
Zn(s)+2Ag+(aq)→2Ag(s)+Zn2+(aq)