Which of the following reaction will readily undergo $S N_{2}$ reaction?

C H_{3} - C H_{2} - O H + H I ⟶ C H_{3} - C H_{2} - I + H_{2} O

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C H_{3} - (C H_{3}) C H - O H + H I ⟶ C H_{3} - (C H_{3}) C H - I + H_{2} O

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C H_{3} - (C H_{3})_{2} C - O H + H I ⟶ C H_{3} - (C H_{3})_{2} C - I + H_{2} O

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All of the above

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Solution

The correct option is A $C H_{3} - C H_{2} - O H + H I ⟶ C H_{3} - C H_{2} - I + H_{2} O$
Generally, simple primary alcohol like methanol, ethanol, etc. follow the $S_{N} 2$ mechanism while reacting with $H I$ due to their less steric in the substrate.

Whereas secondary and tertialy alcohol on reacting with $H I$ follows $S_{N} 1$ due to the stability of the carbocation formed.

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Which will undergo SN2 reaction fastest among the following?

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