Which of the following reactions are not feasible?

$M g + 2 H C l \to M g H_{2} + C l_{2}$

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$2 M g + O_{2} \to 2 M g O$

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$F e + 2 H C l \to F e C l_{2} + H_{2}$

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$A u + 2 H C l \to A u C l_{2} + H_{2}$

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Solution

The correct options are
A
$M g + 2 H C l \to M g H_{2} + C l_{2}$

D
$A u + 2 H C l \to A u C l_{2} + H_{2}$

Metals on reaction with Acids release hydrogen gas.

So, the correct reaction is $M g + 2 H C l \to M g C l_{2} + H_{2}$

Gold (Au) does not react with HCl. Hence the reaction

$A u + 2 H C l \to A u C l_{2} + H_{2}$ is not feasible.

Suggest Corrections

Similar questions

F e + 2 H C l \to F e C l_{2} + H_{2}

F e S + 2 H C l \to F e C l_{2} + H_{2} S

F e + S Δ - \to F e S

N a C l + H_{2} S O_{4} < 200^{o} C - --- \to N a H S O_{4} + H C l

C u S O_{4} + H_{2} S \to C u S + H_{2} S O_{4}

S + H_{2} S O_{4} \to 3 S O_{2} + H_{2} O

F e + 2 H C l \to F e C l_{2} + H_{2}

F e

F e C l_{2}

The following reaction is possible at room temperature.

$A u + 2 H C l \to A u C l_{2} + H_{2}$

H_{2} + C l_{2} ⟶ 2 H C l

2 F e C l_{2} + H_{2} O_{2} + 2 H C l \to 2 F e C l_{3} + 2 H_{2} O

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