Which of the following reactions does not show the correct products of the reaction?

{C H}_{3} - C H = {C H}_{2} H B r - ---- \to P e r o x i d e {C H}_{3} - {C H}_{2} - {C H}_{2} B r

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{C H}_{3} - C H = {C H}_{2} H C l - ---- \to P e r o x i d e {C H}_{3} - {C H}_{2} - {C H}_{2} C l

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{C H}_{3} - C H = {C H}_{2} H B r - -- \to {C H}_{3} - B r | C H - {C H}_{3}

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{C H}_{3} - C H = {C H}_{2} H C l - - \to {C H}_{3} - C H | C l - {C H}_{3}

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Solution

The correct option is C ${C H}_{3} - C H = {C H}_{2} H C l - ---- \to P e r o x i d e {C H}_{3} - {C H}_{2} - {C H}_{2} C l$
Presence of peroxide does not make any difference while reacting with HCl. Only addition of HBr gives anti-Markownikoff's product in presence of peroxide. HCl gives Markownikoff's product only. This is because HCl bond is stronger than HBr and is not cleaved by free radicals.
Thus, (B) is not showing the correct products.

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