Which of the following reactions is/are correctly balanced?

2 C u S O_{4} + 2 N a_{2} C O_{3} + H_{2} O \to C u C O_{3} + C u (O H)_{2} + 2 N a_{2} S O_{4} + C O_{2}

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4 A g + 8 C N^{-} + O_{2} + 2 H_{2} O \to 4 H O^{-} + 4 [A g (C N)_{4}]^{2 -}

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4 {[C o (C N)_{6}]}_{6}^{4} + O_{2} + 2 H_{2} O \to 4 {[C o (C N)_{3}]}_{3}^{3 -} + 4 O H

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3 C u C l_{2} .2 H_{2} O s t r o n g - --- \to h e a t i n g C u O + C u_{2} C l_{2} + 2 H C l + C l_{2} + H_{2} O

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Solution

The correct options are
A $2 C u S O_{4} + 2 N a_{2} C O_{3} + H_{2} O \to C u C O_{3} + C u (O H)_{2} + 2 N a_{2} S O_{4} + C O_{2}$
C $4 {[C o (C N)_{6}]}_{6}^{4} + O_{2} + 2 H_{2} O \to 4 {[C o (C N)_{3}]}_{3}^{3 -} + 4 O H$
D $3 C u C l_{2} .2 H_{2} O s t r o n g - --- \to h e a t i n g C u O + C u_{2} C l_{2} + 2 H C l + C l_{2} + H_{2} O$
The balanced chemical equation are as follows:

A. $2 C u S O_{4} + 2 N a_{2} C O_{3} + H_{2} O \to C u C O_{3} + C u (O H)_{2} + 2 N a_{2} S O_{4} + C O_{2}$
C. $4 {[C o (C N)_{6}]}_{6}^{4 -} + O_{2} + 2 H_{2} O \to 4 {[C o (C N)_{3}]}_{3}^{3 -} + 4 O H$
D. $3 C u C l_{2} .2 H_{2} O s t r o n g - --- \to h e a t i n g C u O + C u_{2} C l_{2} + 2 H C l + C l_{2} + H_{2} O$
As these equations have same number of atoms of every type on both side of the equation as well as the sum of charges of left side and right are same. Hence, these are balanced.

B is not balanced as left side has $8$ negative charges and right side has $4 + 4 \times 2 = 12$ negative charges. Means charges are not same on both side. Hence this is not balanced.

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Similar questions

M + 8 C N^{-} + {2 H}_{2} O + O_{2} \to 4 [M (C N)_{2}]^{-} + 4 O H^{-}

4 M + 8 C N^{-} + 2 H_{2} O + O_{2} \to 4 [M (C N)_{2}] + 4 O H^{-}

M + 8 C N^{-} + 2 H_{2} O + O_{2} \to 4 [M (C N)_{2}]^{-} + 4 O H^{-}

In the equation $4 M + 8 C N^{-} + 2 H_{2} O + O_{2} \to 4 [M (C N)_{2}] + 4 O H^{-}$
Identify metal M:

4 M + 8 C N^{-} + 2 H_{2} O + O_{2} ⟶ 4 [M (C N)_{2}]^{-} + 4 O H^{-}

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