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Preparations and Uses of Sodium Carbonate

Which of the ...

Question

Which of the following reactions is not a part of Solvay's process for preparation of sodium carbonate?

2 N H_{3} + H_{2} O + C O_{2} \to (N H_{4})_{2} C O_{3}

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(N H_{4})_{2} C O_{3} + H_{2} O + C O_{2} \to 2 N H_{4} H C O_{3}

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2 N H_{4} H C O_{3} \to (N H_{4})_{2} C O_{3} + H_{2} O + C O_{2}

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N H_{4} H C O_{3} + N a C l \to N H_{4} C l + N a H C O_{3}

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Solution

The correct option is C $2 N H_{4} H C O_{3} \to (N H_{4})_{2} C O_{3} + H_{2} O + C O_{2}$
The following reaction in solvay's process took place:
$C a C O_{3} \to C a O + C O_{2}$
$2 N H_{3} + C O_{2} + H_{2} O \to {(N H_{4})}_{2} C O_{3}$
${(N H_{4})}_{2} C O_{3} + C O_{2} + H_{2} O \to 2 N H_{4} H C O_{3}$
$N H_{4} H C O_{3} + N a C l \to N a H C O_{3} + N H_{4} C l$
$2 N a H C O_{3} \to N a_{2} C O_{3} + H_{2} O + C O_{2}$
Thus the reaction given in option C is not a part of Solvay's process for preparation of sodium carbonate.

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Similar questions

2 N H_{3} + H_{2} O + C O_{2} ⟶ (N H_{4})_{2} C O_{3} (a q) (a) ⟶ N H_{4} H C O_{3} (b) ⟶ N a H C O_{3} ↓ (d) N a_{2} C O_{3} + C O_{2} + H_{2} O + (c)

(A) Δ - \to (B) + {CO}_{2}

(B) + H_{2} O \to (C) N H_{4} C l - --- \to (D)

(E) + {CO}_{2} \to (F)

(F) + NaCl \to G H e a t - -- \to {Na}_{2} {CO}_{3} + {CO}_{2} + H_{2} O

{(D) is a gas which is soluble in H}_{2} O

N a H C O_{3}

(A) Δ - \to (B) + {CO}_{2}

(B) + H_{2} O \to (C) N H_{4} C l - --- \to (D)

(E) + {CO}_{2} \to (F)

(F) + NaCl \to G H e a t - -- \to {Na}_{2} {CO}_{3} + {CO}_{2} + H_{2} O

{(D) is a gas which is soluble in H}_{2} O

(N a_{2} C O_{3})

N H_{3} + C O_{2} + H_{2} O \to N H_{4} H C O_{3}

N H_{4} H C O_{3} + N a C l \to N H_{4} C l + N a H C O_{3}

2 N a H C O_{3} Δ - \to N a_{2} C O_{3} + H_{2} O + C O_{2}

N a_{2} C O_{3}

N H_{3}

N a H C O_{3} + ? \to N a C l + C O_{2} + H_{2} O

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