Which of the following reactions will not give propane?

C H_{3} C H_{2} C H_{2} C l M g / e t h e r - ----- \to H_{2} P

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C H_{3} C H_{2} C O C l C H_{3} M g X - ----- \to H_{2} P

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C H_{3} C H = C H_{2} B_{2} H_{6} - ------ \to C H_{3} C O O H

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C H_{3} C | H O H - C H_{3} P / H I - -- \to

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Solution

The correct options are
A $C H_{3} C H_{2} C H_{2} C l M g / e t h e r - ----- \to H_{2} P$
B $C H_{3} C H_{2} C O C l C H_{3} M g X - ----- \to H_{2} P$
These two not give propane
$C H_{3} - C H_{2} - C H_{2} - C l M g / e t h e r - ----- \to H_{2} O C H_{3} C H_{2} C H_{2} M g C l$

Suggest Corrections

Similar questions

{C H}_{3} C H (B r) {C H}_{2} {C H}_{3} A l c . K O H - ----- \to

{C H}_{3} C H = C H - {C H}_{3}

{C H}_{2} = C H {C H}_{2} {C H}_{3}

Which of the following compounds gives fastest reaction with HBr and why

(i) (CH3)3 COH

(ii) CH3 CH2 CH2OH

(iii) CH3 CHOH CH3

(iv) CH3 (CH3) CH CH2OH

A g N O_{3}

C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{3} | C H - C H_{3}

C h_{3} C = C - C H_{3}

C H_{3} C H_{2} - C H_{2} - C H_{3}

C H_{3} C H_{2} C = C H

C H_{3} C H = C H_{2}

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