Which of the following reactions will occur, according to the activity series?
1. $F e + A l_{2} O_{3} \to$
2. $C u + M g C l_{2} \to$
3. $C u + A l C l_{3} \to$
4. $F e + H C l \to$

1

and

2

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Only

4

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Only

1

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1, 3

and

4

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Solution

The correct option is A Only $4$
The activity/reactivity series is a list of metals arranged in the order of their decreasing activities. Metals higher in the series displace the metals that come below them in the activity series. $F e$ and $C u$ cannot displace $A l$ or $M g$ as they fall below the given metals in the reactivity series. However, since $F e$ is above hydrogen in the series, it can displace $H$ from the reaction 4.

$F e + 2 H C l \to F e C l_{2} + H_{2}$

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{C u}^{2 +}

{F e}^{2 +}

{C u}^{2 +} + 2 {F e}^{2 +} ⇌ C u + 2 {F e}^{3 +}

{C u}^{2 +}

F e + {C u S O}_{4} ⇌ {F e S O}_{4} + C u

E_{F e / F e}^{o} = 0.44 V; E_{C u / {C u}^{2 +}}^{o} = - 0.337 V

F e + C u S O_{4} ⇌ F e S O_{4} + C u

25^{o} C

E^{0} [F e \to F e^{2 +}) = 0.44 V

E^{0} (C u \to C u^{2 +}) = - 0.337 V

C u + H_{2} {S O}_{4} - \to C u S O_{4} + {S O}_{2} ↑ + H_{2} O

F e + + H_{2} O - \to {F e}_{3} O_{4} + H_{2} ↑

{C H}_{4} + O_{2} \to C O_{2} + H_{2} O

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