Which of the following reactions will result in the formation of a chiral centre in the product ___________.

C H_{3} C H = C H_{2} H B r \to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{2} = C H_{2} + H O B r \to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H_{2} C H = C H_{2} + H B r H_{2} O_{2} - -- \to

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H_{2} C H = C H_{2} + H B r \to

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $C H_{3} C H_{2} C H = C H_{2} + H B r \to$
The reaction between 1-butene and HBr will result in the formation of a chiral centre in the product. The addition occurs according to Markovnokoffs rule. Br is added to C atom bearing less H atoms. The chiral carbon in the product is marked with asterik.. $C H_{3} C H_{2} C^{*} H B r C H_{3}$

Suggest Corrections

Similar questions

C H_{3} C H = C H C H_{3}

C H_{3} C H_{2} C H = C H_{2}

C H_{3} C H_{2} C H = C H_{2} 1. H g (O A c)_{2}, H_{2} O - --------- \to 2. N a B D_{4}

C H_{2} = C H_{2} + H B r \to C H_{3} - C H_{2} - B r

C H_{3} C H_{2} C H_{2} C l + N a I a c e t o n e - --- \to h e a t

(C H_{3})_{3} C B r + K O H e t h a n o l - --- \to h e a t

C H_{3} C H (B r) C H_{2} C H_{3} + N a O H w a t e r - -- \to

(C H_{3})_{3} C B r + K O H e t h a n o l - --- \to h e a t

C_{6} H_{5} O N a + C_{2} H_{5} C l ⟶

C H_{3} C H_{2} C H_{2} O H + S O C l_{2} ⟶

C H_{3} C H_{2} C H = C H_{2} + H B r p e r o x i d e - ---- \to

C H_{3} C H = C (C H_{3})_{2} + H B r ⟶

C H_{3} C H_{2} C H = C H_{2} + C B r_{4} P e r o x i d e s - ----- \to ?

Join BYJU'S Learning Program