Which of the following reactions will yield $2, 2$ -dibromopropane?

C H_{3} - C \equiv C H

+ 2HBr

⟶

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C H_{3} C H = C H B r

+ HBr

⟶

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C H \equiv C H

+ 2HBr

⟶

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C H_{3} - C H = C H_{2}

+ HBr

⟶

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Solution

The correct option is A $C H_{3} - C \equiv C H$ + 2HBr $⟶$
When $2$ moles of $H B r$ add to $1$ mole of propyne, $2, 2$ -dibromopropane is obtained. $B r$ is added to $C$ atom having least number of $H$ atoms.

$C H_{3} - C \equiv C - H H B r - -- \to C H_{3} - C (B r) = C H_{2} H B r - -- \to C H_{3} - C (B r_{2}) - C H_{3} 2, 2 d i b r o m o p r o p a n e$

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C H_{3} - C H = C H_{2} + H B r \to

-------- the product is

Which are free radical reactions

$I . C H_{3} - C H = C H_{2} + H B r P e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} B r I I . C H_{3} - C H = C H_{2} + H B r \to C H_{3} - C H B r - C H_{3} I I I . C H_{3} - C H = C H_{2} + C l_{2} \to C l C H_{2} - C H = C H_{2} I V . C H_{3} - C H_{3} + C l_{2} \to C l C H_{2} - C H_{3}$

C H_{3} - C H_{2} - C H = C H - C H_{2} - C H_{3} + H B r \to

Q. Complete the following reactions:

C H_{3} - C H = C H_{2} + H B r p e r o x i d e \to ?

H_{2} C = C H - C H_{3} + H B r \to ?

Which are free radical reactions

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Which of the following reactions will yield 2,2-dibromopropane?

The correct option is A CH3−C≡CH + 2HBr ⟶When 2 moles of HBr add to 1 mole of propyne, 2,2-dibromopropane is obtained. Br is added to C atom having least number of H atoms.CH3−C≡C−HHBr−−−→CH3−C(Br)=CH2HBr−−−→CH3−C(Br2)−CH32,2 dibromopropane

Which of the following reactions will yield $2, 2$ -dibromopropane?