Question

Which of the following reactions would convert pentan-3-ol (A) into deuterated compound?
$C{H}_3-C{H}_2-\underset{D}{\underset{|}{C}}H-C{H}_2-C{H}_3$

• A. $A\underset{\Delta }{\overset{H_{2}S{O}_4}{\to }}\underset{ii)H_2{O}_2,NaOH}{\overset{i)B{D}_3/THF}{\to }}$
• B. $A\underset{\Delta }{\overset{H_{2}S{O}_4}{\to }}\stackrel{i)D_2/Pt}{\to }$
• C. $A\stackrel{PB{r}_3}{\to }\underset{ii)D_{2}O}{\overset{i)Mg,ether}{\to }}$
• D. $A\stackrel{PB{r}_3}{\to }\stackrel{i)NaOD,D_{2}O}{\to }$

Answer 1

The correct option is C $A\stackrel{PB{r}_3}{\to }\underset{ii)D_{2}O}{\overset{i)Mg,ether}{\to }}$