Question

Which of the following reagent would you choose for the conversion shown below:
$Ar{N}_2^{+}C{l}^{-}⟶ArF$

• A. Only $HB{F}_4$
• B. $HF$
• C. $F_2$
• D. $HB{F}_4/Heat$

Answer 1

Answer: (D)

$HB{F}_4/Heat$

Heating with $NaB{H}_4$ is the only reagent that can produce the above result.