Which of the following reagents can be used to distinguish the $S O_{2}$ and $C O_{2}$ ?

Lime water

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Zinc nitroprusside paste in water

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Potassium iodate and starch

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Acidified potassium dichromate solution

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Solution

The correct options are
B Zinc nitroprusside paste in water
C Potassium iodate and starch
D Acidified potassium dichromate solution
They can be explained as below :
(B) When $S O_{2}$ gas is brought in contact with zinc nitroprusside solution, red colour compound of $Z n [F e (C N)_{5} N O]$ is formed. No colour changes observed with $C O_{2}$ .
(C) When $S O_{2}$ gas is passed through potassium iodate solution, iodine gas is liberated which turns starch solution blue.
$5 S O_{2} + 2 I O_{3}^{-} + 4 H_{2} O I \to I_{2} + 5 S O_{4}^{2 -} + 8 H^{+}$
$I_{2} + s t a r c h \to blue solution$
No colour changes observed with $C O_{2}$ .
(D) $S O_{2}$ gas turns acidified potassium dichromate solution green.
$K_{2} C r_{2} O_{7} + H_{2} S O_{4} + 3 S O_{2} \to K_{2} S O_{4} + C r_{2} (S O_{4})_{3} (g r e e n c o l o u r) + H_{2} O$
No colour changes observed with $C O_{2}$ .
Lime water cannot be used to distinguish between $S O_{2}$ and $C O_{2}$ because both gases turns lime water milky.

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