Which of the following reagents cannot be used to locate the position of triple bond in $C H_{3} - C \equiv C - C H_{3}$ ?

B r_{2} / H_{2} O

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O_{3}

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C u_{2} C l_{2}

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H^{⨁} / K M n O_{4}, Δ

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Solution

The correct option is A $B r_{2} / H_{2} O$
Bromine water is used for test of unsaturation so it tells about unsaturation only not position. Acidic $K M n O_{4}$ and ozone gives oxidation reaction with alkyne so they state about the position of triple bond and forms the corresponding product and ammonical cuprous chloride reacts with end alkyne only.

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Similar questions

Q. Which is the most suitable reagent among the following to distinguish compound (iii) from rest of the compounds?

(i) C H_{3} - C \equiv C - C H_{3}

(i i) C H_{3} - C H_{2} - C H_{2} - C H_{3}

(i i i) C H_{3} - C H_{2} - C \equiv C H

(i v) C H_{3} - C H = C H_{2}

Q. In the following carbocation,

H / C H_{3}

that is most likely to migrate to the positively charged carbon is:

Propene $C H_{3} - C H = C H_{2}$ can be converted into 1-propanol by oxidation. Which set of reagents among the following is ideal to affect the conversion ?

Q. In the following carbocation; the

H / C H_{3}

that is most likely to migrate to the positively charged carbon is:

Q. The stability order of

π

- bond in following alkenes in the increasing order is:

C H_{3} - C H = C H_{2} (I)

C H_{3} - C | C H_{3} = C | C H_{3} - C H_{3} (I I)

C H_{3} - C | C H_{3} = C H_{2} (I I I)

C H_{3} - C | C H_{3} = C H - C H_{3} (I V)

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Which of the following reagents cannot be used to locate the position of triple bond in CH3−C≡C−CH3 ?

Which of the following reagents cannot be used to locate the position of triple bond in $C H_{3} - C \equiv C - C H_{3}$ ?